1. For example:
      2. 2 + 4 = 6 32 – 27 = 5 5 = 32 - 27

      *Relearning to Teach Arithmetic, Susan Jo Russell. 1999.
      Everett Public Schools, 2005
      Addition Strategies
      Adding left to right
      (expanded notation)
      256 + 687
      200 + 600 = 800
      50 + 80 = 130
      6 + 7 = 13
      800 + 130 + 13 = 943
      This algorithm is related to the traditional “carrying” algorithm, which is also a form of adding
      by place, except that traditionally we were taught to start with the ones rather than the largest
      place.*
      Starting with ones of the numbers, then adding on the other number in parts, often (but not
      always) starting with the largest place.*
      256 + 687
      256 + 600 = 856
      856 + 80 = 936
      936 + 7 = 943
      Round one or more of the addends to numbers that are easier to work with, then compensate.*
      256 + 687
      256 + 700 = 956
      956 – 13 = 943
      Transform the entire problem to an equivalent problem that is easier to solve.*
      256 + 687
      256 + 687 = (256 – 13) + (687 + 13)
      243 + 700 = 943
      Please note that students may use larger numbers or chunks once they are more confident with
      their understanding with number. Also, the recording of the numbers is to
      explain
      how they
      solved the problem and can look tedious. Many of the steps can be done
      mentally
      with some
      keeping track on paper if necessary.
      It is important that students eventually learn to read all common notations, including both
      vertical and horizontal notations for addition, subtraction, and multiplication, as well as the
      various notations for division. However, they need to be secure enough to interpret these
      notations correctly while still relying on their own mathematically sound procedures to solve
      problems notated in any of these ways.*
      For example:
      2 + 4 = 6
      32 – 27 = 5
      5 = 32 - 27
      2
      32
      12
      12 x 7 = 84
      +4
      - 27
      x 7
      6
      5
      84
      6
      24 ÷ 4 = 6
      24/4 = 6
      4)24

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